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Simpson's rule
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Revision as of 02:47, December 31, 2008
11 bytes added
,
02:47, December 31, 2008
m
→Example 2
:
fixed typo
Line 32:
Line 32:
:<math>f\left ({{4+12}\over{2}}\right ) = f(8) = \frac{3(8)+11}{8^2-8-6} = {35\over50} = {7\over10} </math>
:<math>f\left ({{4+12}\over{2}}\right ) = f(8) = \frac{3(8)+11}{8^2-8-6} = {35\over50} = {7\over10} </math>
<br />Now we can solve:
<br />Now we can solve:
−
:<math>\left ({12-4 \over 6}\right ) \left ( {23 \over 6} + 4 \left( {7\over10} \right)+ {47 \over 126} \right ) = \left ( {4\over3} \right ) ({2207\over315}) \approx 9.34179... </math>
+
:<math>\left ({12-4 \over 6}\right ) \left ( {23 \over 6} + 4 \left( {7\over10} \right)+ {47 \over 126} \right ) = \left ( {4\over3} \right )
\left
({2207\over315}
\right
) \approx 9.34179... </math>
<br />As the function given does not resemble a parabola, the answer we get is completely off of the real answer, which is:
<br />As the function given does not resemble a parabola, the answer we get is completely off of the real answer, which is:
: <math>\approx 7.94160...</math>
: <math>\approx 7.94160...</math>
WilliamBeason
257
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