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2 bytes added ,  01:40, January 8, 2009
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An observation of a far-off object is typically made at a given moment and from a given place, and so ds=dt=0. So the above equation simplifies to:
 
An observation of a far-off object is typically made at a given moment and from a given place, and so ds=dt=0. So the above equation simplifies to:
   −
<math> - dr^2 + \Bigg(1 + \frac{\Psi}{\tau^2}\Bigg) \tau dv^2 = 0</math>
+
<math> - dr^2 + \Bigg(1 + \frac{\Psi}{\tau^2}\Bigg) \tau^2 dv^2 = 0</math>
    
Carmeli's solution is:
 
Carmeli's solution is:
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