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4 bytes removed ,  03:32, January 12, 2010
use its more common name, prepare for move
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A '''Lagrangian multiplier''' is a constant, usually represented by the Greek symbol lambda (λ), which is part of the formula for finding an extreme value of a function ''f(x,y)'' subject to a constraint ''g(x,y)''.  For example, the method of Lagrange multipliers can help determine the maximum area of a rectangle that can be fit inside a given circle represented by ''g(x,y) = x<sup>2</sup> + y<sup>2</sup>''.
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A '''Lagrange multiplier''' is a constant, usually represented by the Greek symbol lambda (λ), which is part of the formula for finding an extreme value of a function ''f(x,y)'' subject to a constraint ''g(x,y)''.  For example, the method of Lagrange multipliers can help determine the maximum area of a rectangle that can be fit inside a given circle represented by ''g(x,y) = x<sup>2</sup> + y<sup>2</sup>''.
    
The points at which [[extrema]] occur for a function ''f(x,y)'' subject to the constraint ''g(x,y)'' are the common solutions to:
 
The points at which [[extrema]] occur for a function ''f(x,y)'' subject to the constraint ''g(x,y)'' are the common solutions to:
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''Problem'': What is the shape and dimension of the largest rectangle that fits within a circle having a radius equal to the square root of 2?
 
''Problem'': What is the shape and dimension of the largest rectangle that fits within a circle having a radius equal to the square root of 2?
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''Solution'':  ''g(x,y) = x<sup>2</sup> + y<sup>2</sup> - 2 = 0''.  We want to maximize the area of a rectangle.  Assuming symmetry about the origin (we could always map a solution to a symmetric one), the area ''f(x,y)'' that we want to maximize equals 2x times 2y:  ''f(x,y) = 4xy''.  From the equation for the Lagrangian multiplier above, and setting the ''x'' and ''y'' coefficients equal to each other, we can generate these two equations:
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''Solution'':  ''g(x,y) = x<sup>2</sup> + y<sup>2</sup> - 2 = 0''.  We want to maximize the area of a rectangle.  Assuming symmetry about the origin (we could always map a solution to a symmetric one), the area ''f(x,y)'' that we want to maximize equals 2x times 2y:  ''f(x,y) = 4xy''.  From the equation for the Lagrange multiplier above, and setting the ''x'' and ''y'' coefficients equal to each other, we can generate these two equations:
    
:4y = λ2x
 
:4y = λ2x
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