or in two dimensions, just <math>\frac{\partial f_1}{\partial x} + \frac{\partial f_2}{\partial y}</math>. Note that if we were to define a "vector" <math>\nabla = \vec{i}\partial_x +\vec{j}\partial_y + \vec{k}\partial_z </math>, we would have <math>\operatorname{div}\ \vec{F} = \nabla \cdot \vec{F} </math>. Note that this isn't technically a vector, since the component are not number but differential operators, and the kind of "multiplication" we're doing isn't really multiplication, since you can't multiply an operator by a function; instead we're differentiating the components. Nevertheless, it's a handy notational convenience, and it actually does point to a deeper truth we won't begin to address in this course, so we'll continue to use <math>\nabla \cdot \vec{F} </math> for the divergence. | or in two dimensions, just <math>\frac{\partial f_1}{\partial x} + \frac{\partial f_2}{\partial y}</math>. Note that if we were to define a "vector" <math>\nabla = \vec{i}\partial_x +\vec{j}\partial_y + \vec{k}\partial_z </math>, we would have <math>\operatorname{div}\ \vec{F} = \nabla \cdot \vec{F} </math>. Note that this isn't technically a vector, since the component are not number but differential operators, and the kind of "multiplication" we're doing isn't really multiplication, since you can't multiply an operator by a function; instead we're differentiating the components. Nevertheless, it's a handy notational convenience, and it actually does point to a deeper truth we won't begin to address in this course, so we'll continue to use <math>\nabla \cdot \vec{F} </math> for the divergence. |