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No change in size ,  14:10, March 19, 2010
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:<math>(2ax + b)^2 = b^2 - 4ac</math> (group each side)
 
:<math>(2ax + b)^2 = b^2 - 4ac</math> (group each side)
   −
:<math>2ax + b = \pm \sqrt{b^2 - 4ac}</math> (take sqaure root, allow for both roots)
+
:<math>2ax + b = \pm \sqrt{b^2 - 4ac}</math> (take square root, allow for both roots)
    
:<math>2ax = -b \pm \sqrt{b^2 - 4ac}</math> (subtract b)
 
:<math>2ax = -b \pm \sqrt{b^2 - 4ac}</math> (subtract b)
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