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→Basis of determining values
:::::Thank you. Well done!--[[User:Aschlafly|Andy Schlafly]] 14:00, 28 May 2010 (EDT)
:::::Thank you. Well done!--[[User:Aschlafly|Andy Schlafly]] 14:00, 28 May 2010 (EDT)
::::::That equation doesn't make sense. There is no time variable in the function. Placing any time in the equation will not affect the outcome. For example, if the time is 2 years, that will give us <math>E(2)={\operatorname{c}100\over\operatorname{c}+o} \!</math>. But it will turn out the same if we make time 3, 4, 5, or any other amount of years because time is not factored into the equation. I think a better way to express the equation would be <math>E(t,c,o)={\operatorname{ct}\over\operatorname{c}+o} \!</math>% where ''t'' is time in years. Now we can have the function as such:<math>E(1/2,5,10)={\operatorname{(5)(1/2)}\over\operatorname{5}+10} \!</math> Which gives us a censorability of 16.7% or .17 [[User:JonS|JonS]] 19:17, 5 June 2010 (EDT)
==100% Censorable?==
==100% Censorable?==