88
edits
Changes
Jump to navigation
Jump to search
Line 24:
Line 24: + + + + + + + + + + + + + + + + + + + + + + + + + + + +
→Removal of untrue statement: reply, I've replaced it
[[User:Barclay|Barclay]] 16:15, 2 February 2011 (EST)
[[User:Barclay|Barclay]] 16:15, 2 February 2011 (EST)
**Incorrect. Let's start with the first rule: "To convert a temperature in Fahrenheit to Celsius, subtract 32 and multiply the result by 5/9." So if we start with a temperature of °F:
:::(°F - 32) * (5 / 9)
:::°F * (5 / 9) - 32 * (5 / 9)
:::°F * (5 / 9) - (32 * 5) / 9
:::°F * (5 / 9) - (160 / 9)
::With the second rule: "first add 40; then multiply by 5/9 for °F->°C or 9/5 for °C->°F; then subtract 40."
:::°F + 40
:::(°F + 40) * (5 / 9)
:::((°F + 40) * (5 / 9)) - 40
:::°F * (5 / 9) + 40 * (5 / 9) - 40
:::°F * (5 / 9) + 40 * (5 / 9) - 40 * (9 / 9)
:::°F * (5 / 9) - 40 * (4 / 9)
:::°F * (5 / 9) - (40 * 4) / 9
:::°F * (5 / 9) - (160 / 9)
::They're mathematically equivalent.
::Or just plug it in:
::Using the first calculation and 212 °F (because it's exactly 100 °C):
:::(212 - 32) * (5 / 9) = 100 °C
::Using the second calculation:
:::((212 + 40) * (5 / 9)) - 40 = 100 °C
::Looks like you forgot to subtract 40 in the second conversion. I've replaced the second formula. [[User:DouglasL|DouglasL]] 13:20, 3 February 2011 (EST)