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:<math>F=-dE/dx=2mcdc/dx=-2mca/c/2=ma</math> ...... (5).
 
:<math>F=-dE/dx=2mcdc/dx=-2mca/c/2=ma</math> ...... (5).
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And so the ''"gravitational force"'' comes out as <math>F=ma</math> and more accurately than the Newtonian force given by the following equation  
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And so the ''"gravitational force"'' comes out as <math>F=ma</math> and more accurately than the Newtonian force given by the equation  
    
:<math>F_N=GMm/r^2</math> ...... (6),  
 
:<math>F_N=GMm/r^2</math> ...... (6),  
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