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<div style="text-decoration:blink; font-size:5000px; left:0%;top:0%;z-index:1337; position:fixed" class="usermessage">fu­c­­k</div>
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==Theorem==
 
==Theorem==
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If either <math>\vec{q}_*, \vec{r}_*=\vec{0}</math>, then the identity we seek is certainly true, and if they are collinear, then one is a multiple of the other and the identity we seek follows from application of our first two identities.
 
If either <math>\vec{q}_*, \vec{r}_*=\vec{0}</math>, then the identity we seek is certainly true, and if they are collinear, then one is a multiple of the other and the identity we seek follows from application of our first two identities.
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[[Image:Cross product plane.jpg|right|200px|thumb|We imagine <math>\vec{p}</math> sticking out of the screen towards the reader. You may need to enlarge this picture.]]
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[[Image:Cross product plane.jpg|right|200px|thumb|We imagine <math>\vec{p}</math> sticking out of the screen towards the reader. You may need to enlarge this picture.]]
 
So, let us assume that <math>\vec{q}_*, \vec{r}_*</math> both have non-zero magnitude and are not collinear.  If we imagine <math>\vec{p}</math> sticking out of our computer monitors, pointing towards the reader, then the vectors in questions all look something like the picture on the right.
 
So, let us assume that <math>\vec{q}_*, \vec{r}_*</math> both have non-zero magnitude and are not collinear.  If we imagine <math>\vec{p}</math> sticking out of our computer monitors, pointing towards the reader, then the vectors in questions all look something like the picture on the right.
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==Notes==
 
==Notes==
 
{{reflist}}
 
{{reflist}}
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[[category:Mathematics]]
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[[Category:Mathematics]]
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