Substituting <math>1/R^2</math> math>\Lambda</math> and solving the equation with initial conditions <math>E(r=0)=E_o</math> and <math>(dE/dr)(r=0)=-E_o/R</math> (meaning selecting a solution that makes physical sense) one gets
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Substituting <math>1/R^2</math> for <math>\Lambda</math> and solving the equation with initial conditions <math>E(r=0)=E_o</math> and <math>(dE/dr)(r=0)=-E_o/R</math> (meaning selecting a solution that makes physical sense) one gets