Block, SkipCaptcha, Automoderated users, edit, rollback
3,135
edits
Changes
Jump to navigation
Jump to search
Line 96:
Line 96: +
→A Counterexample: Speed of Extremely Energetic Neutrinos: restore edit from User:GregG/RSS 5, edit #50 from backup
The mass of a neutrino is about 0.44x10<sup>-36</sup>kilograms. (Normally all of these things are measured in more convenient units such as Giga-electron-Volts, but that makes implicit use of E=mc<sup>2</sup>. If we don't accept that, we have to do the calculations under classical physics, using SI (meter/kilogram/second) units.) The neutrinos were accelerated to an energy of about 17GeV, or .27x10<sup>-8</sup>Joules. Using the classical formula <math>\mathrm{E} = \frac{1}{2}mv^2</math>, we get v=110x10<sup>12</sup>meters per second. This is about 370,000 times the speed of light.
The mass of a neutrino is about 0.44x10<sup>-36</sup>kilograms. (Normally all of these things are measured in more convenient units such as Giga-electron-Volts, but that makes implicit use of E=mc<sup>2</sup>. If we don't accept that, we have to do the calculations under classical physics, using SI (meter/kilogram/second) units.) The neutrinos were accelerated to an energy of about 17GeV, or .27x10<sup>-8</sup>Joules. Using the classical formula <math>\mathrm{E} = \frac{1}{2}mv^2</math>, we get v=110x10<sup>12</sup>meters per second. This is about 370,000 times the speed of light.
However, the classical formula breaks down at speeds close to <math>c</math>, and indeed, as the speed of a massive object approaches <math>c</math>, the object's kinetic energy approaches <math>+\infty</math>.
Several scientists have gone on record stating that the neutrinos, which have mass, travel at precisely the speed of light. This disproves the [[Theory of Relativity]] and the claim that '''E=mc<sup>2</sup>'''.
Several scientists have gone on record stating that the neutrinos, which have mass, travel at precisely the speed of light. This disproves the [[Theory of Relativity]] and the claim that '''E=mc<sup>2</sup>'''.