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Conditional probability
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Revision as of 20:15, May 6, 2012
24 bytes added
,
20:15, May 6, 2012
clarify notation
Line 19:
Line 19:
A. There are now 4 red balls and 3 greens, so: 4/7
A. There are now 4 red balls and 3 greens, so: 4/7
−
In the second case, the question requires a conditional probability: P(red|red).
+
In the second case, the question requires a conditional probability: P(red
on 2nd draw
|red
on 1st draw
).
===See also===
===See also===
GregG
Block, SkipCaptcha,
Automoderated users
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