Difference between revisions of "Conservation of angular momentum"

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:<math>\mathbf{KE_i}= \frac{I}{2}\times\omega^2</math>  
 
:<math>\mathbf{KE_i}= \frac{I}{2}\times\omega^2</math>  
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 +
Solving the above four equations yields:
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:<math>\mathbf{cos\theta} = 1 - \frac{I\times{\omega^2}}{g\times{L}\times{(m+M)}}</math>
 
[[category:physics]]
 
[[category:physics]]

Revision as of 02:59, November 18, 2007

The conservation of angular momentum holds that the angular momentum just prior to a collision is the same as the angular momentum just after a collision.

Example

Imagine a rod of length l and mass M suspensed from one end vertically, and that a small block mass having velocity v and mass m collides with the other end and sticks to it. The maximum angle of displacement of the rod from the vertical axis can be calculated using the conservation of angular momentum:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathbf{L_i}=\mathbf{L_f}}

After the collision, there is conservation of energy such that the final potential energy of the rod (with the sticking block mass) equals the initial kinetic energy just after the collision:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathbf{U_f}= \mathbf{KE_i}}

Now solve the the two sides of the above equation separately:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathbf{U_f}= \mathbf{U_{rod}}+\mathbf{U_{block}}}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathbf{U_{rod}}= \frac{L}{2}\times(1-cos\theta)\times{M}\times{g}}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathbf{U_{block}}= L\times(1-cos\theta)\times{m}\times{g}}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathbf{KE_i}= \frac{I}{2}\times\omega^2}

Solving the above four equations yields:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathbf{cos\theta} = 1 - \frac{I\times{\omega^2}}{g\times{L}\times{(m+M)}}}