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condition (3) follows from (1) per talk page, updated accordingly
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It is necessary to express probability as a density function for a variable or parameter which may take on a continuum of values so that the total probability covering the entire domain of support may converge to a finite value.  The counterpart for a discretely distributed variable is the [[probability mass function]].
 
It is necessary to express probability as a density function for a variable or parameter which may take on a continuum of values so that the total probability covering the entire domain of support may converge to a finite value.  The counterpart for a discretely distributed variable is the [[probability mass function]].
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In order to qualify as a ''probability density function'', such a function must meet the following criteria:
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In order to qualify as a ''probability density function'', such a function must satisfy the following two criteria:
 
      
(1) <math> f(x) \geq 0 </math>  <math> \forall x </math>  inside the domain of support.
 
(1) <math> f(x) \geq 0 </math>  <math> \forall x </math>  inside the domain of support.
      
(2) <math> \int_{-\infty}^\infty \,f(x)\,dx = 1. </math>  i.e., finitely convergent (to unity by convention).
 
(2) <math> \int_{-\infty}^\infty \,f(x)\,dx = 1. </math>  i.e., finitely convergent (to unity by convention).
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From the first condition above, it necessarily follows that:
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(3) <math> \int_{-\infty}^a \,f(x)\,dx \leq \int_{-\infty}^b \,f(x)\,dx </math>  for a<b,  i.e., is non-decreasing
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<math> \int_{-\infty}^a \,f(x)\,dx \leq \int_{-\infty}^b \,f(x)\,dx </math>  for a<b,  i.e., is non-decreasing
 
      
Such a function leads to the definition of an associated [[cumulative distribution function]].
 
Such a function leads to the definition of an associated [[cumulative distribution function]].
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