Difference between revisions of "Talk:Fermat's Last Theorem"

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(why mention criticism later retracted?)
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"Any proof which uses the axiom of choice can be transformed into one that doesn't"?!  Lol.  If C is the axiom of choice, then C (vacuously) proves C.  By your assertion, that proof can be 'transformed' into a proof not using C, which means you can prove C from ZF, which is a contradiction.  Really, lol.  [[User:Tomkup32|Tomkup32]] 09:26, 9 December 2009 (EST)
 
"Any proof which uses the axiom of choice can be transformed into one that doesn't"?!  Lol.  If C is the axiom of choice, then C (vacuously) proves C.  By your assertion, that proof can be 'transformed' into a proof not using C, which means you can prove C from ZF, which is a contradiction.  Really, lol.  [[User:Tomkup32|Tomkup32]] 09:26, 9 December 2009 (EST)
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==Marilyn vos Savant==
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Is there any purpose in the last few sentences mentioning Marilyn vos Savant's criticism that she retracted a few years later? I don't think her mistaken criticism is relevant to Fermat's theorem. [[User:Yoritomo|Yoritomo]] 10:15, 17 December 2009 (EST)

Revision as of 15:15, December 17, 2009

The first computer program I wrote - between high school and college - generated solutions to the Pythagorean Theorem. I guess I should have programmed it to count them, too. --Ed Poor Talk 21:25, 20 December 2007 (EST)

Axiom of choice

Any proof which uses the axiom of choice can be transformed into a proof that doesn't. Granted, it will be a somewhat more complicated proof, but it always works, and that's a fact. That is the reason that AC is much less controversial these days than it was, in the early 1900s.

There is a complete explanation of the process and the proof that it's reliable here.

Also, the profoundly intuitive trichotomy is equivalent to AC, so be careful what you call controversial. BenjB 20:29, 27 January 2008 (EST)


"Any proof which uses the axiom of choice can be transformed into one that doesn't"?! Lol. If C is the axiom of choice, then C (vacuously) proves C. By your assertion, that proof can be 'transformed' into a proof not using C, which means you can prove C from ZF, which is a contradiction. Really, lol. Tomkup32 09:26, 9 December 2009 (EST)

Marilyn vos Savant

Is there any purpose in the last few sentences mentioning Marilyn vos Savant's criticism that she retracted a few years later? I don't think her mistaken criticism is relevant to Fermat's theorem. Yoritomo 10:15, 17 December 2009 (EST)