Difference between revisions of "Lagrange multiplier"
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and ''g(x,y) = 0''. | and ''g(x,y) = 0''. | ||
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| + | == Example == | ||
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| + | ''Problem'': What is the shape and dimension of the largest rectangle that fits within a circle having a radius equal to the square root of 2? | ||
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| + | ''Solution'': ''g(x,y) = x<sup>2</sup> + y<sup>2</sup> - 2 = 0''. We want to maximize the area of a rectangle. Assuming symmetry about the origin (we could always map a solution to a symmetric one), the area ''f(x,y)'' that we want to maximize equals 2x times 2y: ''f(x,y) = 4xy''. From the equation for the Lagrangian multiplier above, and setting the ''x'' and ''y'' coefficients equal to each other, we can generate these two equations: | ||
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| + | :4y = \lambda 2x | ||
| + | :4x = \lambda 2y | ||
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| + | Solving each for lambda (λ) demonstrates that x must be equal to y, and plugging that into the equation for ''g'' yields: | ||
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| + | :2x<sup>2</sup> = 2 | ||
| + | :x = 1 = y | ||
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| + | Then do not forget to include the maximum area in your answer, which is ''f(1,1) = 4(1)(1) = 4. | ||
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[[Category:calculus]] | [[Category:calculus]] | ||
[[Category:mathematics]] | [[Category:mathematics]] | ||
Revision as of 23:52, December 25, 2009
A Lagrangian multiplier is a constant, usually represented by the Greek symbol lambda (λ), which is part of the formula for finding an extreme value of a function f(x,y) subject to a constraint g(x,y). For example, the method of Lagrange multipliers can help determine the maximum area of a rectangle that can be fit inside a given circle represented by g(x,y) = x2 + y2.
The points at which extrema occur for a function f(x,y) subject to the constraint g(x,y) are the common solutions to:
and g(x,y) = 0.
Example
Problem: What is the shape and dimension of the largest rectangle that fits within a circle having a radius equal to the square root of 2?
Solution: g(x,y) = x2 + y2 - 2 = 0. We want to maximize the area of a rectangle. Assuming symmetry about the origin (we could always map a solution to a symmetric one), the area f(x,y) that we want to maximize equals 2x times 2y: f(x,y) = 4xy. From the equation for the Lagrangian multiplier above, and setting the x and y coefficients equal to each other, we can generate these two equations:
- 4y = \lambda 2x
- 4x = \lambda 2y
Solving each for lambda (λ) demonstrates that x must be equal to y, and plugging that into the equation for g yields:
- 2x2 = 2
- x = 1 = y
Then do not forget to include the maximum area in your answer, which is f(1,1) = 4(1)(1) = 4.