SkipCaptcha, nsSupply_SidersR, nsSupply_Siders_
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::::::That equation doesn't make sense. There is no time variable in the function. Placing any time in the equation will not affect the outcome. For example, if the time is 2 years, that will give us <math>E(2)={\operatorname{c}100\over\operatorname{c}+o} \!</math>. But it will turn out the same if we make time 3, 4, 5, or any other amount of years because time is not factored into the equation. I think a better way to express the equation would be <math>E(t,c,o)={\operatorname{ct}\over\operatorname{c}+o} \!</math>% where ''t'' is time in years. Now we can have the function as such:<math>E(1/2,5,10)={\operatorname{(5)(1/2)}\over\operatorname{5}+10} \!</math> Which gives us a censorability of 16.7% or .17 [[User:JonS|JonS]] 19:17, 5 June 2010 (EDT)
::::::That equation doesn't make sense. There is no time variable in the function. Placing any time in the equation will not affect the outcome. For example, if the time is 2 years, that will give us <math>E(2)={\operatorname{c}100\over\operatorname{c}+o} \!</math>. But it will turn out the same if we make time 3, 4, 5, or any other amount of years because time is not factored into the equation. I think a better way to express the equation would be <math>E(t,c,o)={\operatorname{ct}\over\operatorname{c}+o} \!</math>% where ''t'' is time in years. Now we can have the function as such:<math>E(1/2,5,10)={\operatorname{(5)(1/2)}\over\operatorname{5}+10} \!</math> Which gives us a censorability of 16.7% or .17 [[User:JonS|JonS]] 19:17, 5 June 2010 (EDT)
:::::::I'm no math major, but I don't know that time needs to be factored in; times censored over opportunities to be censored seems logical to me. Why would you multiply the result of ''that'' equation by time? If something is censored 50% of the time for 5 years ... does that mean that the censorability is 2.50? That's impossible; the percent would be 250%.--<small>[[User:Iduan|<span style="color: #FFCCCC; background: #660000">I]][[User_talk:Iduan|<span style="color:#CCCCFF; background:#000033">Duan]]</span></span></small> 22:22, 5 June 2010 (EDT)
==100% Censorable?==
==100% Censorable?==