Difference between revisions of "Conservative vector field"

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#REDIRECT [[conservative vector]]
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A '''conservative field''' or '''conservative vector field''' has a [[curl]] of zero:
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:<math>\nabla \times \vec V = (\ \ \frac{\partial V_z}{\partial y} - \frac{\partial V_y}{\partial z},\ \ \ \ \frac{\partial V_x}{\partial z} - \frac{\partial V_z}{\partial x},\ \ \ \ \frac{\partial V_y}{\partial x} - \frac{\partial V_x}{\partial y}\ \ ) = 0</math>
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Its significance is that the line integral of a conservative field, such as a physical force, is independent of the path chosen.  In physics, this means that the potential energy (which is determined by a conservative force field) of a particle at a given position is independent of how a particle was moved to its position.
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[[Category:vector analysis]]
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[[Category:calculus]]
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[[Category:mathematics]]

Revision as of 16:59, December 26, 2009

A conservative field or conservative vector field has a curl of zero:

<math>\nabla \times \vec V = (\ \ \frac{\partial V_z}{\partial y} - \frac{\partial V_y}{\partial z},\ \ \ \ \frac{\partial V_x}{\partial z} - \frac{\partial V_z}{\partial x},\ \ \ \ \frac{\partial V_y}{\partial x} - \frac{\partial V_x}{\partial y}\ \ ) = 0</math>

Its significance is that the line integral of a conservative field, such as a physical force, is independent of the path chosen. In physics, this means that the potential energy (which is determined by a conservative force field) of a particle at a given position is independent of how a particle was moved to its position.