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:<math>d^2E/dr = \Lambda E </math> ...... (1)
 
:<math>d^2E/dr = \Lambda E </math> ...... (1)
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Substituting <math>1/R^2</math> math>\Lambda</math> and solving the equation with initial conditions <math>E(r=0)=E_o</math> and <math>(dE/dr)(r=0)=-E_o/R</math> (meaning selecting a solution that makes physical sense) one gets  
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Substituting <math>1/R^2</math> for <math>\Lambda</math> and solving the equation with initial conditions <math>E(r=0)=E_o</math> and <math>(dE/dr)(r=0)=-E_o/R</math> (meaning selecting a solution that makes physical sense) one gets  
    
:<math>E / E_o=exp(-r/R)</math> ...... (2)
 
:<math>E / E_o=exp(-r/R)</math> ...... (2)
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