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A. There are now 4 red balls and 3 greens, so: 4/7
A. There are now 4 red balls and 3 greens, so: 4/7
In the second case, the question requires a conditional probability: P(red|red).
In the second case, the question requires a conditional probability: P(red on 2nd draw|red on 1st draw).
===See also===
===See also===