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→‎A Reducible 2nd-Degree Polynomial Denominator: Spelling/Grammar Check, typos fixed: Therefore → Therefore,
Line 52: Line 52:  
:<big><math>\frac{3x+11}{(x-3)(x+2)}=\frac{A(x+2)+B(x-3)}{(x-3)(x+2)}</math></big>
 
:<big><math>\frac{3x+11}{(x-3)(x+2)}=\frac{A(x+2)+B(x-3)}{(x-3)(x+2)}</math></big>
   −
Therefore the problem can be restated,
+
Therefore, the problem can be restated,
    
:<big><math>3x+11=A(x+2)+B(x-3)</math></big>
 
:<big><math>3x+11=A(x+2)+B(x-3)</math></big>
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