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| | {{Math-h}} | | {{Math-h}} |
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| − | The '''Fourier transformation''' (often called the '''Fourier transform''' or '''Fourier integral''') is an invertible [[integral]] transformation that decomposes a square integrable, [[piecewise continuous]] functions on a [[topological group]] into a linear combination of basis elements. It can be thought of as the ultimate extension of the [[Fourier series]], in which the interval of periodicity becomes infinitely long and the "coefficients" infinitely close together, becoming a function instead of an infinite series. | + | The '''Fourier transformation''' (often called the '''Fourier transform''' or '''Fourier integral''') is an invertible [[integral]] transformation that decomposes a square integrable, piecewise continuous functions on a [[topological group]] into a linear combination of basis elements. It can be thought of as the ultimate extension of the [[Fourier series]], in which the interval of periodicity becomes infinitely long and the "coefficients" infinitely close together, becoming a function instead of an infinite series. |
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| | Often, functions which are difficult to analyze in one topological group become much easier to analyze when transformed to another topological group. | | Often, functions which are difficult to analyze in one topological group become much easier to analyze when transformed to another topological group. |
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| − | The formulas usually favored by mathematicians are the "normalized" form. Given a function f(k) defined on the entire real line, its Fourier transform g(k) is given by: | + | The formulas usually favored by mathematicians are the "normalized" form. Given a function <math>f(t)</math> defined on the entire real line, its Fourier transform <math>g(\omega)</math> is given by: |
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| − | :<math>g(k) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{\infty} f(x) e^{-ixk}\, dx</math> | + | :<math>\mathcal{F}[f(t)](\omega) = g(\omega) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{\infty} f(t) e^{-i \omega t}\, dt</math> |
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| | The inverse transform, that recovers the original function, is: | | The inverse transform, that recovers the original function, is: |
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| − | :<math>f(x) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{\infty} g(k) e^{ixk}\, dk</math> | + | :<math>\mathcal{F}^{-1}[g(\omega)](t) = f(t) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{\infty} g(\omega) e^{i \omega t}\, d \omega</math> |
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| | The constants in front of the integrals are arbitrary, so long as their product is <math>1/2\pi</math>. In order to make the forward and inverse transforms as similar as possible, an oft-used convention is to set them both equal to <math>1/\sqrt{2\pi}</math>. | | The constants in front of the integrals are arbitrary, so long as their product is <math>1/2\pi</math>. In order to make the forward and inverse transforms as similar as possible, an oft-used convention is to set them both equal to <math>1/\sqrt{2\pi}</math>. |
| | + | The Fourier transform of a function <math>f(t)</math> is often denoted with a hat: <math>\hat f(\omega)</math> |
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| | ==Discrete Fourier transformation== | | ==Discrete Fourier transformation== |