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Partial fractions in integration
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Revision as of 18:12, August 8, 2016
1 byte added
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18:12, August 8, 2016
→A Reducible 2nd-Degree Polynomial Denominator
:
Spelling/Grammar Check, typos fixed: Therefore → Therefore,
Line 52:
Line 52:
:<big><math>\frac{3x+11}{(x-3)(x+2)}=\frac{A(x+2)+B(x-3)}{(x-3)(x+2)}</math></big>
:<big><math>\frac{3x+11}{(x-3)(x+2)}=\frac{A(x+2)+B(x-3)}{(x-3)(x+2)}</math></big>
−
Therefore the problem can be restated,
+
Therefore
,
the problem can be restated,
:<big><math>3x+11=A(x+2)+B(x-3)</math></big>
:<big><math>3x+11=A(x+2)+B(x-3)</math></big>
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