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Revision as of 14:47, December 30, 2008
This article details several methods of intergration for advanced high school or early university student, each with an example.
Contents
Integration by Parts
For a more detailed treatment, see Integration by parts.
Integration by parts is a special technique to facilitate the integration of the product of two functions that otherwise lack an obvious integral. This technique can be proven with the product rule.
The rule for integration by parts is stated as follows:
This rule is often useful when one function is a power of x and the other function is a trigonometric function or e raised to a power of x.
Note that it may be necessary to repeat the integration by parts several times, one for each power of x.
Partial Fractions
For a more detailed treatment, see Partial fractions in integration.
Integration by partial fractions is a technique to facilitate the integration of a rational expression by partial fraction decomposition.
Given an integral
where 
and 
are both polynomials, integration by partial fractions shows how to separate the problem into multiple integrals before integrating.
Algebraic Substitution
Integration by Algebraic Substitution is a technique to facilitate the integration of a rational expression by substituting a more complicated expression with a variable.
Given an integral
We can substitute the term :
with a u. Giving us
We then take the derivative of u with respect to x,
We then set the terms equal to du,
Now we are ready to rewrite the integral,
We can rewrite the integral this way due to the subsitution of the x terms with the u terms.
Now we can solve the integral in terms of u.
Now we replace u with the term : to get,
We can check this by taking the derivative of :
,
Trigonometric Substitution
Integration by Trigonometric Substitution is a technique to facilitate the integration of a rational expression by substituting a more complicated radical expression with a trigonometric expression.
Given an integral
By looking at the radical we can determine that it represents the base of a right triangle by understanding the Pythagorean theorem.
where 3 is the hypotenuse and x is the height of the triangle.
This allows us to rewrite the expression to :
. This allows us to substitute x with :
.
Now to do the substitution
And by use of trigonometric identities we know that
Therefore
We are not done yet, we must also take the derivative of :
By partial derivatives we move the :
over.
Now we are ready to rewrite our integral.
From our trigonometric expression :
we can see that
giving us the final solution.
